Maybe this will be referred to later in this thread (I’m still clearing my backlog…)…
…but I had the feeling to jump in the math^^
[quote=“Cybnate, post:57, topic:648”][…]
They are talking about a randomiser factor +Coin age to solve blocks, double the coinage doubles your chance. I got that.
Ok, let’s do some examples ignoring any complex randomisers to equal chances to start with. Let’s say you have just one block in a certain period.
And the following people have their wallet set to minting:
5 people (A) have 100 coinage, 4 people (B) have 50 coinage, 1 © has 24 coinage and 1 (D) only 1 coinage.
Throwing this into the pool; A has double the chance of solving a block over B. B would have double the chance over C.
But what is the actual chance for A, B and C? Total coinage is 5100+450+124+11= 725
So someone in group A would have a 100/725 chance = ~13.79% chance. An individual in B would have 50/725 = 6.7% C would have 24/725 = 3.3% and D only 1/725 = 0.13%
Let’s keep these 11 individuals and add more blocks into it. With Peercoin we seem to have 6 blocks every hour. However it seems there are on average 5 to 6 blocks PoS and 1 block PoW in an hour (this needs further statistical proof). Let’s assume 5 blocks in hour for PoS. A day has 24 hours. 5 blocks x 24 = 120 blocks/days
So what are the chances now? To me each individual would have 120x times more chance (draws) to solve a block in a day then if there was only one.
So someone from group A would on average successfully mint a block after 100/16.55% = 6.04 blocks.
C have to wait for 100/6.7% = 14,93 blocks to successfully mint.
However D 100/0.13% = 769 blocks, so the chance of D minting a block on that day is 0.13% * 120 blocks = 15.6%[/quote]
If A has the chance of solving one block at the given difficulty of 16.55% (0.1655), he has a chance of 83.45% (0.8345) of not solving it.
This makes for a series of n blocks a total chance of 0.8345^n for not solving any block.
After 6.04 blocks (knowing that there are no 0.04 blocks that can be solved ) the total chance of solving at least 1 block is 1-0.8345^6.04=0.66 -> 66%
You miss the “compound interest” of luck for solving blocks
If you ask about the average time to solve a block, I think the question would be: at which number of blocks (n) is the chance at least 50% to have successfully minted at least one block.
For participant A that leads to:
1-0.8345^n=0.5
0.8345^n=0.5
log(0.8345^n)=log(0.5)
n*log(0.8345)=log(0.5)
n=log(0.5)/log(0.8345)
-> n=3.83
Beginning with the 4th block in a row the chance to have minted at least one of them is above 50%!
[quote=“Cybnate, post:57, topic:648”][…]
Here I need some help in mathematics.
[…]
If you’re still with me after reading the above then you’re probably a mathematician or a very big proof-of-stake/PPC fan ;-)[/quote]
I am - both a fan of math and Peercoin/PoS!